(2x-5)(x^2-4x+1)=

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Solution for (2x-5)(x^2-4x+1)= equation: 


Simplifying
(2x + -5)(x2 + -4x + 1) = 0

Reorder the terms:
(-5 + 2x)(x2 + -4x + 1) = 0

Reorder the terms:
(-5 + 2x)(1 + -4x + x2) = 0

Multiply (-5 + 2x) * (1 + -4x + x2)
(-5(1 + -4x + x2) + 2x * (1 + -4x + x2)) = 0
((1 * -5 + -4x * -5 + x2 * -5) + 2x * (1 + -4x + x2)) = 0
((-5 + 20x + -5x2) + 2x * (1 + -4x + x2)) = 0
(-5 + 20x + -5x2 + (1 * 2x + -4x * 2x + x2 * 2x)) = 0
(-5 + 20x + -5x2 + (2x + -8x2 + 2x3)) = 0

Reorder the terms:
(-5 + 20x + 2x + -5x2 + -8x2 + 2x3) = 0

Combine like terms: 20x + 2x = 22x
(-5 + 22x + -5x2 + -8x2 + 2x3) = 0

Combine like terms: -5x2 + -8x2 = -13x2
(-5 + 22x + -13x2 + 2x3) = 0

Solving
-5 + 22x + -13x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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